PHP实现两种排课方式

admin3年前PHP教程33

两种排课方式:

固定每周的固定时间上课总共上几个周,每周上课时间比较个性化

第一种排课比较好实现,简要代码如下:


/**
     * 生成日期列表
     *
     * @param  int $startDate 开始日期 时间戳格式
     * @param  array $timeList 课时计划列表
       [
        {
            "start_at": "09:09", //开课时间
            "end_at": "10:09",   //结束时间
            "week_at": 1         //周几
        },
        {
            "start_at": "12:09", //开课时间
            "end_at": "13:09",   //结束时间
            "week_at": 1         //周几
        },
        {
            "start_at": "09:09",
            "end_at": "10:09",
            "week_at": 5
        }
       ]
     * @param  int $amount 课时计划数量
     * @param  int $skipHoliday 跳过节假日
     *
     * @return array
     */
    public function generateDateList($startDate, $timeList, $amount, $skipHoliday = 0)
    {
        // 计算开始日期是周几
        $startDateWeek = intval(date('N', $startDate));
 
        //规范化课时数据 week_at 做key的三维数组
        foreach ($timeList as $item) {
 
            $weekAt = $item['week_at'];
            
            array_splice($item, 0, 0, $weekAt);
            $key = array_shift($item);
            $weeksTime[$key][] = $item;
            $item = null;
        }
 
        unset($timeList);
 
        if (empty($weeksTime)) {
            $this->addError('课时计划数据为空');
            return false;
        }
 
        //设置跳过假期,获取开始日期之后的节假日
        if ($skipHoliday) {
            $holiday = new Holiday();
            $holidayData = $holiday->getHolidayList($startDate);
            $holiday = null;
            unset($holiday);
        }
 
        $nowTime = time();
        $list = array();
 
        for ($weekStartTime = $startDate, $count = 0; $count < $amount; $weekStartTime += 86400 * 7) {
 
            //$currentWeek :周几
            foreach ($weeksTime as $currentWeek => $weekTime) {
 
                foreach ($weekTime as $time) {
 
                    //算出对应的日期时间戳
                    $currentDateTime = $weekStartTime + (($startDateWeek <= $currentWeek ? ($currentWeek - $startDateWeek) : (7 - $startDateWeek + $currentWeek)) * 86400);
                    //对应的日期 = 开始时间 + ((开始时间对应周 <= 数据对应的周几 ? (数据对应的周几 - 开始时间对应周) :(7 - 开始时间对应周 + 数据对应的周几)) * 86400)
                    //假期跳过排课
                    if ($skipHoliday && !empty($holidayData)) {
                        $startUnix = $currentDateTime + $time['start_at'] * 3600;  //开始时间
                        $endUnix = $currentDateTime + $time['end_at'] * 3600;     //结束时间
 
                        $skip = false;
 
                        //选择跳过节假日,且节假日与当前课程时间有重叠跳过
                        foreach ($holidayData as $item) {
                            if (($item['start_at'] < $endUnix && $item['end_at'] > $startUnix) || ($item['start_at'] === $startUnix && $item['end_at'] === $endUnix)) {
                                $skip = true;
                                continue;
                            }
                        }
 
                        if ($skip) {
                            continue;
                        }
                    }
 
                    $currentDate = date('Y/m/d', $currentDateTime);
                    $startAt = strtotime($currentDate . $time['start_at'] . ':00');
                    $endAt = strtotime($currentDate . $time['end_at'] . ':00');
 
                    if($startAt < $nowTime || $endAt < $nowTime){
                        $this->addError('上课时间不能小于当前时间');
                        return false;
                    }
 
                    $list[] = [
                        'date_at' => $currentDateTime, //日期
                        'week_at' => $currentWeek,     //周几
                        'start_at' => $startAt,
                        'end_at' => $endAt
                    ];
 
                    $count++;
 
                    if ($count >= $amount) {
                        break 3;
                    }
                }
            }
        }
 
        $weeksTime = null;
        unset($weeksTime);
 
        return $list;
    }

(例子,只用来展示数据结构)假如总共5节课时,从6-25日开始排课,每周一、周六上课:

(例子,只用来展示数据结构)排课结果为:


第二种排课方式稍微麻烦一点,简要代码如下:


/**
     * 生成日期列表
     *
     * @param  int $startDate 开始日期 时间戳格式
     * @param  array $taskList 任务列表
    [
        {
            "start_at": "09:09", //开始上课时间
            "end_at": "10:09",   //结束时间
            "week_at": 1,        //周几
            "week_number": 1     //第几周
        },
        {
            "start_at": "09:09",
            "end_at": "10:09",
            "week_at": 2,
            "week_number": 1
        },
        {
            "start_at": "09:09",
            "end_at": "10:09",
            "week_at": 1,
            "week_number": 3
        }
    ]
     *
     * @return array
     */
    public function generateDateList($startDate, $taskList)
    {
        // 计算开始日期是周几
        $startDateWeek = intval(date('N', $startDate));
 
        $list = [];
        $nowTime = time();
        $weekSign = $week = 0;
 
        foreach($taskList as $key => $task){
 
            if($task['week_number'] > $weekSign && $task['week_number'] != $week){
                $weekSign = $task['week_number'] - $week;
            }
 
            //计算每条数据对应的日期 $key == 0:确定第一周第一节课是在本周还是下一周
            if($key == 0 || $task['week_number'] == $week){
 
                if($task['week'] >= $startDateWeek){
                    $task['date_at'] = $startDate +
                        (($weekSign - 1) * 7 + ($task['week'] - $startDateWeek)) * 86400;
                }else{
                    $task['date_at'] = $startDate +
                        (($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
                }
            }else{
                if($task['week'] > $startDateWeek){
                    $task['date_at'] = $startDate +
                        (($weekSign) * 7 + ($task['week'] - $startDateWeek)) * 86400;
                }else{
                    $task['date_at'] = $startDate +
                        (($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
                }
            }
 
            $startDateWeek = intval(date('N', $task['date_at']));
 
            $week = $task['week_number'];
 
            $startDate = $task['date_at'];
 
            $dateAt = date('Y/m/d', $task['date_at']);
 
            $startAt = strtotime($dateAt . '00:00:00');
            if($task['start_at']){
                $startAt = strtotime($dateAt . $task['start_at'] . ':00');
            }
 
            $endAt = strtotime($dateAt . '23:59:59');
            if($task['end_at']){
                $endAt = strtotime($dateAt . $task['end_at'] . ':00');
            }
 
            if($startAt < $nowTime || $endAt < $nowTime){
                $this->addError('上课时间不能小于当前时间');
                return false;
            }
 
            $task['start_at'] = $startAt;
            $task['end_at'] = $endAt;
 
            //生成课时数据
            $list[] = [
                    'date_at' => $task['date_at'],
                    'week_at' => $task['week'],
                    'start_at' => $startAt,
                    'end_at' => $endAt
                ];
        }
 
        return $list;
    }

(例子,只用来展示数据结构)排课数据:

(例子,只用来展示数据结构) 排课结果:

到此这篇关于PHP实现两种排课方式的文章就介绍到这了,更多相关PHP实现排课内容请搜索以前的文章或继续浏览下面的相关文章希望大家以后多多支持!

免责声明:本文内容来自用户上传并发布,站点仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。请核实广告和内容真实性,谨慎使用。

相关文章

10个常见网站安全攻击手段及防御方法?美国高防服务器如何防御网络攻击?

在某种程度上,互联网上的每个网站都容易遭受安全攻击。从人为失误到网络罪犯团伙发起的复杂攻击均在威胁范围之内。网络攻击者最主要的动机是求财。无论你运营的是电子商务项目还是简单的小型商业网站,潜在攻击的风...

linux系统的新加披gpu服务器怎么查看配置信息

linux系统的新加披gpu服务器怎么查看配置信息?查看操作系统信息:cat/etc/redhat-release操作系统详细发行信息:lsb_release-aCPU信息:lscpuCPU具体型号c...

浅谈laravel中间件的创建思路

Laravel 中间件提供了一种机制在不修改逻辑代码的情况下,中断原本程序流程,通过中间件来处理一些事件,或者扩展一些功能。比如日志中间件可以方便的记录请求和响应日志,而不需要去更改逻辑代码。那么我们...

PHP获取文件属性的最简单方法

1、filesize($filename) 返回指定文件大小。如果成功,会返回文件大小的字节数;如果失败,则返回 FALSE。2345<?phpheader("content-type...

php的Snoopy类案例讲解

php的Snoopy类获取请求网页里面的所有链接,直接使用fetchlinks就可以,获取所有文本信息使用fetchtext(其内部还是使用正则表达式在进行处理),还有其它较多的功能,如模拟提交表单等...

PHP优化教程之解决嵌套问题

在开发过程中,我们经常遇到一对多的场景,例如:查询订单列表,并且展示订单详情商品、数量数据思路0:传统做法a. 查询订单列表b. 遍历订单详情$orderList = select * from or...